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(C) The force $F$ required to maintain the motion of the conveyor belt is given by the rate of change of momentum.Since the velocity $v$ is constant,t

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$Mv \ N$

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(C) The force $F$ required to maintain the motion of the conveyor belt is given by the rate of change of momentum.Since the velocity $v$ is constant,the force is given by $F = \frac{dp}{dt} = \frac{d}{dt}(mv)$.Using the product rule,$F = v \frac{dm}{dt} + m \frac{dv}{dt}$.Since the velocity $v$ is constant,$\frac{dv}{dt} = 0$.Given that the rate of mass deposition is $\frac{dm}{dt} = M \ kg/s$,we substitute these values into the equation:$F = v \cdot M + m \cdot 0 = Mv$.Therefore,the force required to keep the conveyor belt moving at a constant velocity $v$ is $Mv \ N$.

Sand is being dropped on a conveyor belt at the rate of $M \ kg/s$. The force necessary to keep the belt moving with a constant velocity of $v \ m/s$ will be

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